Milovana.com

Nezhul wrote:
It's just that I forgor that on this formula the combinations of 2 similar numbers can not be achieved. In reality they can, and we just make it 15+6=21

.

So this doesn't tell you your formula does not represent this situation?
Do you really not see 6-4 is different from 4-6?

Nezhul wrote:no, why? 2 and 12 can be achieved. You can't achieve 1 because each die will roll at least 1, the sum will be at least two (unless, off course, under some misterious circumstances one of the dies will stay floating in the air)

It's just that I forgor that on this formula the combinations of 2 similar numbers can not be achieved. In reality they can, and we just make it 15+6=21

my table above showed how may combinations can be there to get that sum. thus, if you want

1 - can not be achieved
2 - is only 1+1
3 - is only 1+2
4 - is eather 3+1 or 2+2
5 - is eather 4+1 or 3+2
6 - is eather 5+1 or 4+2 or 3+3
7 - is eather 6+1 or 5+2 or 4+3
and so on, and it degrades because
10 is 5+5 or 6+4 - there's no 3rd combination for 10.
11 is ONLY 5+6.

I think I will be happier if ballsfull will use my die and not yours,
As you claim six one is the same as one six


Sum of two dice
When you have two dice.
Imagine two dice, red and green.
One thing that you can do is work out what the total of the dice is.
The dice experiment allows you to simulate throwing pairs of dice and see what the result is.
This is a good introduction to probability, since you can see which combinations are more likely.
But the real world, or even a simulated real world, never matches completely with calculated probability.

So how do we calculate it?
The first thing is to work out what the range is.
You can't have a total less than 2 (both dice being 1) and you can't have a total more than 12 (both dice being 6).
The easiest way to see what the probabilities is to write out the possible totals.
There are 36 of them in all (6 x 6).

Total on dice Pairs of dice Probability
2 1+1 1/36 = 3%
3 1+2, 2+1 2/36 = 6%
4 1+3, 2+2, 3+1 3/36 = 8%
5 1+4, 2+3, 3+2, 4+1 4/36 = 11%
6 1+,5 2+4, 3+3, 4+2, 5+1 5/36 = 14%
7 1+6, 2+5, 3+4, 4+3, 5+2, 6+1 6/36 = 17%
8 2+6, 3+5, 4+4, 5+3, 6+2 5/36 = 14%
9 3+6, 4+5, 5+4, 6+3 4/36 = 11%
10 4+6, 5+5, 6+4 3/36 = 8%
11 5+6, 6+5 2/36 = 6%
12 6+6 1/36 = 3%


fundamentally thick
Les

36 is when the order MATTERS. then YES it IS 36.

Moreover if it's red and green die, there'd be 42 combinations, because 1red and 1green are different elements, making it total 12 elements we are talking about, finding out pairs.

But in our case all that matters is the SUM value. We need only the sum. If 2 dies was rolled as 5 and 2 - in THIS game it doesnt't matter at all, wich of them rolled 5 and wich rolled 2. All that matters that both dies summary rolled 7.

That's not right. If you use 36 combinations (meening it matters wich die rolled wich number, it'd have to be:

2 1+1 , 1+1 2/36 = 6%

Strangely, you don't forget this one somwhere.
3 1+2, 2+1 2/36 = 6%
and yet still ignore it in the other places

Don't argue any more. Because I'v studied it for years, and I'm right.

Nezhul wrote:Don't argue any more. Because I'v studied it for years, and I'm right.

Unfortunately, if you went to Vegas with your probabilities, you'd also go ~broke~....

As Les has repeatedly tried to demonstrate, and no matter WHAT ELSE your math tells you, 7 is the "sweet spot", with 6 and 8 close behind....
And in this particular game, if someone is unfortunate to work themselves up into about the 9 spot, you'll start to see a little panic in their eyes... And appropriately so!!

Regardless, first roll is today.... LATER today...
(and as I appreciate that "today" means different times to different people, for reference, I'm in the US, in the CST zone...)

Nezhul, you are completely wrong. Sorry.

And it's so, so obvious.

Maybe this link can convince you: http://www-cs-students.stanford.edu/~ni ... tlers.html

Nezhul wrote: But in our case all that matters is the SUM value. We need only the sum. If 2 dies was rolled as 5 and 2 - in THIS game it doesnt't matter at all, wich of them rolled 5 and wich rolled 2. All that matters that both dies summary rolled 7.

What matter is the probabilty of a sum occuring. And 2+5 and 5+2 are distinct events.

As for counting 1+1 AND 1+1 as you suggested.. that doesn't make any sense.

To make it very simple:
Each number on a single dice has a chance of 1/6. In order to get the sum of two, both dice have to land on 1. Thus: 1/6 * 1/6 = 1/36
For a sum of 3, one of the dice has to land on 1, the other on 2. It doesn't matter which one is 1 and which one is two. Consequently: (1/6*1/6) is the chance for "1+2" to occur. (1/6*1/6) is also the chance for "2+1" to occur. Add those up and you get 2/36 or 1/18.

I don't know how to make it any clearer. If you are still in doubt, just write a program that simulates dicerolls and let it roll a couple of million times or whatever and check the distribution.


Also: This discussion may be ruining the thread, maybe an admin could move it into a seperate thread? :)

Damn-it!!! The roll is in!! And it's NOT ~me~...

The dice roll was a FIVE!!

cbtslaveboy2 gets to CUM!!!

Cbtslaveboy2, you are not allowed to apply again until AFTER the next roll, which will be in 2-3 days..

And as noted before, players below that person will then move up one slot, leaving the #0 slot open.
The FIRST person (not currently in the game) to request a slot AFTER the roll will be entered in the #0 slot, and we all patiently wait for the next roll, doing our daily edges as per our slot number...
Slot #0 will ALWAYS be a "no-touch" position.
The new listing is:

Slot #0 open - (no touching)
Slot #1 - Lady Anne (02/19/11)
Slot #2 - edding (02/19/11)
Slot #3 - puppet (02/18/11)
Slot #4 - les (02/17/11)
Slot #5 - [name removed] (??????)
Slot #6 - lonewanderer (02/18/11)
Slot #7 - ballsfull (02/19/11)
Slot #8 - ballsfull (02/19/11)
Slot #9 - ballsfull (02/19/11)
Slot #10- ballsfull (02/19/11)
Slot #11- ballsfull (02/19/11)
Slot #12- ballsfull (02/19/11)

The number is the number to be rolled for you to get permission to cum, and also the number of edges you must complete each day.

Enjoy your edges, boys....AND girl!!

So now I can be added?

also, Nezhul is right, purely because the 2 die are the same, so orders don't matter.

hornydude123 wrote:So now I can be added?

also, Nezhul is right, purely because the 2 die are the same, so orders don't matter.

Yes, on the next update, you will be in slot #0... No touching as of now, hornydude....

And now I know how they afford all those fancy buildings, shows, and freebies in Vegas....

yay! touching again, and one step closer to having a chance. yay!

Lady Anne wrote:yay! touching again, and one step closer to having a chance. yay!

"So you're saying there's a chance"....

But again, glad to have you on-board, Lady Anne....

I'm ~sure~ all the horny boys would love to know how you're doing with your edging and denial and all...

I don't know what to say. It's just too stupid.
YES if we take green and red die, there are 2 total variants of dropping 2+1 (the other 1+2)
However that's if we CARE of the order they fall. tha fact is that in this game to get number 3, we are interested in the situation when numbers 2&1 can drop. We don't care wich die dropped 2, and wich dropped 1 whatsoever. We care only that ONE OF THEM dropped 2, and the OTHER dropped 1 at the same time. This doesn't add or take from the odds, because it's just the COMBINATION of numbers we are interested in, not the order. There are total 21 COMBINATIONS that can be dropped with 2 d6. Not 36 of them.

Study math and logic better, really. I'm done with explaining the simpliest shit to you.

sweet guess todays my lucky day

Too bad ballsfull didn't tell us how the five was rolled. Actually, there are two different possibilities: The green die rolling a 4 and the red die rolling a 1, the green die rolling a 3 and the red die rolling a 2, the green die rolling a 2 and the red die rolling a3, the green die rolling a 1 and the red die rolling a 4

Even if the odds are bad, maybe I'll try to join the game after one of the next rolls.

Telly wrote:Too bad ballsfull didn't tell us how the five was rolled.

Telly wrote:Even if the odds are bad, maybe I'll try to join the game after one of the next rolls.

Odds get BETTER, as you move up to the 7 slot....
It's the 9+ that'll get you to start sweating...

But the odds of anyone actually getting there are very, very low.... hehehehehehe

Add me in for the next 0. Last O: 16th Feb 11. You know that the idea of skipping over 7 with bad luck will triple my arousal.

N.